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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 28 May 2019
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      Student: Can I please get these points back?? The +C never matters! Me:pic.twitter.com/sJ6LteuaKc

      20 replies 47 retweets 219 likes
    2. Jeffrey Aguilera‏ @scala_ninja 28 May 2019
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      Replying to @InertialObservr

      The +C still doesn't matter, since the results only differ by a constant ... 1.

      1 reply 0 retweets 0 likes
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 28 May 2019
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      Replying to @scala_ninja

      You literally just argued why the constant matters

      1 reply 0 retweets 3 likes
    4. Jeffrey Aguilera‏ @scala_ninja 28 May 2019
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      Replying to @InertialObservr

      No, I literally pointed out that when someone says the integral of X is Y and Y does not have an arbitrary constant, one is immediately assumed. Just like EVERY SINGLE INTEGRAL in Gradshteyn and Ryzhik.

      1 reply 0 retweets 1 like
    5. 〈 Berger | Dillon 〉‏ @InertialObservr 28 May 2019
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      Replying to @scala_ninja

      I agree it’s not necessary when you know what you’re doing. But an exam is literally a demonstration that you know what you’re doing.

      1 reply 0 retweets 0 likes
    6. Jeffrey Aguilera‏ @scala_ninja 28 May 2019
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      Replying to @InertialObservr

      I would think the act of integrating something non-trivial would be the demonstration, not mastery of some pedantic bookkeeping. And to be fair, every integral should have a different constant. The fact that C is "an arbitrary constant" is just cargo cult.

      2 replies 0 retweets 0 likes
    7. 〈 Berger | Dillon 〉‏ @InertialObservr 28 May 2019
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      Replying to @scala_ninja

      The integration constant *is* an arbitrary constant, so I don't quite understand your cult assertion. Addressing your other concern, that's why the +C is always worth a small amount. In my experience I've found that the students whose only complaint is "+C" do just fine.

      1 reply 0 retweets 1 like
    8. Jeffrey Aguilera‏ @scala_ninja 28 May 2019
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      Replying to @InertialObservr

      +A, +B, -D, -(the value of the integral at zero) ... these are all valid constants. I would rather have someone that can get the hard part of an integral right, rather than someone that religiously parrots a +C even if the rest is wrong.

      2 replies 0 retweets 1 like
      〈 Berger | Dillon 〉‏ @InertialObservr 28 May 2019
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      Replying to @scala_ninja

      I don't know what assertions you're trying to force me into saying. But if you read my responses you're changing the actual things I'm asserting.

      5:41 PM - 28 May 2019
      1 reply 0 retweets 0 likes

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