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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    1. 〈 Berger | Dillon 〉‏ @InertialObservr 17 May 2019
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      In Classical Mechanics, the state of the system is completely determined by its position and momentum (𝐱(𝑡),𝐩(t)). 👉Phase space is the space of all (𝐱(𝑡),𝐩(t)) 👉An orbit in phase space corresponds to a system that returns to its initial conditions (e.g. oscillators)pic.twitter.com/GGNH9R1ISl

      4 replies 13 retweets 54 likes
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    2. Oqaqiq‏ @oqaqiq 17 May 2019
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      Replying to @InertialObservr

      This example seems false to me.

      1 reply 0 retweets 0 likes
    3. 〈 Berger | Dillon 〉‏ @InertialObservr 17 May 2019
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      Replying to @oqaqiq

      What do you mean?

      1 reply 0 retweets 0 likes
    4. Oqaqiq‏ @oqaqiq 17 May 2019
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      Replying to @InertialObservr

      When x grows, p should be positive. When x decreases, p should be negative. Am I naive? Maybe this stuff just doesn’t work like that, because of some aspect of quantum mechanics. I don’t know.

      1 reply 0 retweets 0 likes
    5. Oqaqiq‏ @oqaqiq 17 May 2019
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      Replying to @oqaqiq @InertialObservr

      I’m assuming p=m*dx/dt and maybe that is foolish. I’m not sure.

      1 reply 0 retweets 0 likes
    6. 〈 Berger | Dillon 〉‏ @InertialObservr 17 May 2019
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      Replying to @oqaqiq

      If you have an oscillator x= Acos(ωt) and p = -Αωsin(ωt) and so there's no reason in general you would expect x>0 --> p>0

      1 reply 0 retweets 0 likes
    7. Amogh Anakru‏ @lmaogh 17 May 2019
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      Replying to @InertialObservr @oqaqiq

      If x and p are of that form, should it not trace out an ellipse (not oblique) going clockwise? (x is abscissa, p is ordinate) This way, x is decreasing iff p is negative. I think this is what @opaqiq was pointing out.

      1 reply 0 retweets 0 likes
      〈 Berger | Dillon 〉‏ @InertialObservr 17 May 2019
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      Replying to @lmaogh @oqaqiq

      Right, I'm not asserting that this is a standard harmonic oscillator.

      1:28 PM - 17 May 2019
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