Property 1: Hermitian operators have all real eigenvalues. Here Ω is a hermitian operator and |Ωᵢ〉is one of its eigenvectors.pic.twitter.com/Jk3NmPfdN0
Show this thread
In Quantum Mechanics, Ω is called an 𝐨𝐛𝐬𝐞𝐫𝐯𝐚𝐛𝐥𝐞 only if it can be represented by a Hermitian operator acting on the Hilbert space.pic.twitter.com/SLvTZ3SPUT
-
-
-
Property 2: Eigenvectors of a hermitian operator Ω with *distinct* eigenvalues are orthogonal.pic.twitter.com/fceXleLAB7
Show this thread
End of conversation
New conversation -
-
-
This Tweet is unavailable.
-
stay tuned
End of conversation
-
-
-
One question: it must be Hermitian to satisfy that the expected value is real? But I think there are non Hermitian operators with real spectrum. So what prohibits that an operator associated to an observable is not Hermitic? Btw sorry for my English.
-
Good question.. there's actually some work being done on PT invariant operators as a "generalization" of hermitian operators.. I need to look it cause i forget up so I'll get back to you
- 1 more reply
New conversation -
-
-
I call these "Hamlet" operators, because they always wonder if this is a dagger they see before them... I'll show myself out...
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
-
-
Esto es cierto si el espacio de Hilbert es finito dimensional, si el espacio de Hilbert es de dimensión infinita, entonces el operador debe ser autoadjunto de tal manera que el dominio del operador y de su adjunto coincidan.
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.