Go ahead, square the integrand. π doesn't mind.pic.twitter.com/Cx5HCElH4q
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You forgot to define "I". I(0) = 0 => I(alpha) = alpha*pi => I(1) = pi
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I define I on the first line
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Should the last line of the proof have I(1) rather than I?
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Should be another equality I := I(1)
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about backwards? start with sin(x)/x and move to sin^2(x)/x^2
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Just read from bottom to top !
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Sorry. I do not understand why I(0) = 0 implies that?. Shouldn't be I(1) instead?.
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There is an arbitrary constant of integration in α, and to say that it's 0 we need a condition such as I(0) = 0
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good one
Thanks. Twitter will use this to make your timeline better. UndoUndo
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But the squared integrand is strictly less than the non-squared, except at x=0.
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No, only in absolute value, because when sin(x)/x < 0 then the square is greater.
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