We can then write the derivative as a function of its exponential and the identity operator.
pretty neat..
pic.twitter.com/xMcU2MNbgF
You can add location information to your Tweets, such as your city or precise location, from the web and via third-party applications. You always have the option to delete your Tweet location history. Learn more
We can then write the derivative as a function of its exponential and the identity operator.
pretty neat..
pic.twitter.com/xMcU2MNbgF
Does this formula have any special meaning?
In quantum mechanics it shows that the momentum operator is the generator of translations
In the first equality it looks like you are Taylor expanding a derivative operator? What sort of theorem allows one to do it?
There is no theorem, this is how the exponential of a linear operator is defined. That is, they are defined through the taylor expansion
@robertghrist has a good discussion about this on a recent @myfavethm podcast and linking stability in continuous time and discrete time
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.