hahha do you have a feature request?
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Replying to @InertialObservr
more Lie groups and why they're important for physics SU(2) SO(3) ...E8?!!?!
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Replying to @Corey_Yanofsky
yes yes yes!!! but I can't just jump right into those guys haha.. U(1) is just as important as those as it's isomorphic to SO(2)!
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Replying to @InertialObservr
so i mean if you already have a plan then that's the "more" i want i'm just an impatient little vampire girl
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Replying to @Corey_Yanofsky @InertialObservr
was originally looking for oliver but i went with claudia when her gif came uppic.twitter.com/nQ0LHTxOzX
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Replying to @Corey_Yanofsky @InertialObservr
(and i'm still noodling over your stupid distance-from-point-on-x-axis-to-point-on-unit-circle integral; not sure if you think of it that way but that's one of the things it is)
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Replying to @InertialObservr
yep 1 - 2*a*cos(θ) + a^2 = sin^2(θ) + cos^2(θ) - 2*a*cos(θ) + a^2 = sin^2(θ) + [a - cos(θ)]^2 = the square of the distance from (a, 0) to (cos(θ), sin(θ)) maybe that has nothing to do with how to solve it but it's what immediately came to mind
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Replying to @Corey_Yanofsky
Neat! If you could solve it that way it'd be pretty cool
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Replying to @InertialObservr
i feel like i'm supposed to take the derivative wrt a under the integral sign or maybe IBP; both can get rid of the log i've looked at the multiple angle formulae and i've tried the trick that solves the beta integral my trig-identity-fu is too weak
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you're getting warmer..
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