〈 Berger | Dillon 〉

that's not true either it's a wiggler

The integrand is a wiggler..Did you plot the integrand or the integral as a function of alpha? Because the latter is the thing that should be scale invariant

i didn't exactly plot it as a function of alpha, but it's everywhere positive (in the domain of integration) for alpha = 1 and dips below zero for alpha = 2

see? wiggler

Right, but that doesn’t say anything about scale invariance

oh, the integral is definitely scale invariant, sorry ...but then isn't scale invariance exactly what your differentiation under the integral sign proves? /me is confused

I am not sure if it answers your question but if you differentiate a function, say f(alpha), with respect to alpha and the result is zero, than f is constant with respect to alpha, so f(alpha) = c and f(0) = f(1) = c. They use this result to prove that I(alpha) = I(0) = I(1).

Isn’t that what I did? Lol