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InertialObservr's profile
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
〈 Berger | Dillon 〉
@InertialObservr

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〈 Berger | Dillon 〉

@InertialObservr

PhD student of Theoretical Particle Physics @UCIrvine l @NSF Fellow l Physics & Math Animations l Patreon: https://www.patreon.com/inertialobserver …

DC → CA
youtube.com/c/InertialObse…
Joined August 2015

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    〈 Berger | Dillon 〉‏ @InertialObservr 20 Jan 2019
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    I'm starting a series on "Quantum Mechanics Basics". Feel free to comment with any questions about the posted material. Be sure to stay tuned and enjoy!pic.twitter.com/NHmeD3kR4H

    12:39 PM - 20 Jan 2019
    • 107 Retweets
    • 470 Likes
    • Liam Bright ☀ mickai #MassTestingNowPH Dennis Yao HazaLand Antrix Wiley Matts 🧢 🌊 Pastafarian Spaceologist Imaduddin Alawiy Craig Arko Josue
    16 replies 107 retweets 470 likes
      1. New conversation
      2. 〈 Berger | Dillon 〉‏ @InertialObservr 21 Jan 2019
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        Quantum Mechanics Basics #2: Completeness. Here I go over the notion of "completeness", using the familiar standard basis for ℝ³, and making use of our new QM vector notation introduced in QM Basics #1. Equation (2) is extremely important and we will use it time and time again.pic.twitter.com/JfI3SKgUOC

        1 reply 8 retweets 67 likes
        Show this thread
      3. 〈 Berger | Dillon 〉‏ @InertialObservr 26 Jan 2019
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        Quantum Mechanics Basics #3: Wave Functions & Probabilities.pic.twitter.com/vMcSNzlKoJ

        2 replies 6 retweets 58 likes
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      4. 〈 Berger | Dillon 〉‏ @InertialObservr 26 Jan 2019
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        It should be noted that, for pedagogical purposes, I say that |<x|ψ>|^2 is the probability that the particle *at* position x. Since x is a continuous variable, the gory truth is actually that "|<x|ψ>|^2*dx is the probability that the particle lies in the interval [x, x+dx]"

        1 reply 1 retweet 37 likes
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      5. 〈 Berger | Dillon 〉‏ @InertialObservr 27 Jan 2019
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        Quantum Mechanics Basics #3(a): Example and Application of Wave Functions & Probabilitiespic.twitter.com/xYQuYIQb12

        1 reply 2 retweets 49 likes
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      6. 〈 Berger | Dillon 〉‏ @InertialObservr 27 Jan 2019
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        Quantum Mechanics Basics #4: The Schrödinger Equation & Time Evolutionpic.twitter.com/vNDomHkrew

        3 replies 4 retweets 53 likes
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      7. End of conversation
      1. New conversation
      2. Herb da Hegelian‏ @HerbertHitchens 20 Jan 2019
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        Replying to @InertialObservr

        What is an “observable” or should I just say “observer” in QM?

        1 reply 0 retweets 2 likes
      3. 〈 Berger | Dillon 〉‏ @InertialObservr 20 Jan 2019
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        Replying to @HerbertHitchens

        Another good question. An observable is simply a dynamical value that one can measure (e.g. momentum, position, spin, angular momentum etc.). These are represented by hermitian operators because that enforces that the eigenvalues (what we measure) always be real

        2 replies 1 retweet 15 likes
      4. 13 more replies
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      2. Priti‏ @CosmoPriti 20 Jan 2019
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        Replying to @InertialObservr

        Is Euclidean space a part of the Hilbert space?

        1 reply 0 retweets 3 likes
      3. 〈 Berger | Dillon 〉‏ @InertialObservr 20 Jan 2019
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        Replying to @CosmoPriti

        Good question. To answer your question I would have to follow up with "which Hilbert space?". That is, every particle has different degrees of freedom and these are reflected in the nature of the Hilbert space.

        1 reply 0 retweets 3 likes
      4. 2 more replies
      1. New conversation
      2. Scoffing Mathematician  🏳️‍🌈 🇪🇺‏ @BarbaraFantechi 22 Oct 2019
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        Replying to @InertialObservr

        are you assuming each eigenvalue has multiplicity one? How do you choose one eigenvector |a> in the eigenspace of the eigenvalue a?

        1 reply 0 retweets 2 likes
      3. 〈 Berger | Dillon 〉‏ @InertialObservr 22 Oct 2019
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        Replying to @BarbaraFantechi

        no the eigenvalues are allowed to be degenerate, in which case an orthonormal basis can still be found by Graham Schmidt Orthogonalization and eigenvector is usually not chosen in QM, rather the representation of the operator O, and the eigenstates are the EVs

        1 reply 0 retweets 5 likes
      4. 5 more replies

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