This response from @openAI is true but misleading.
In the fully unscrambled cube condition, with an uninstrumented cube (ie no sensors), success rate was zero.https://twitter.com/woj_zaremba/status/1186149419739037696 …
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Replying to @GaryMarcus @OpenAI
I was wondering about that. Havent gotten around to reading the paper yet but does it say 0% in there? I figured given Woj's reply & since prev SOTA was 0, that he meant it was a non-zero but lower than the instrumented case.
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Replying to @GaneshNatesh @OpenAI
it's in the table 6, bottom right corner:pic.twitter.com/F1hnhn1yFT
7:51 AM - 22 Oct 2019
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