If you can get the c' and c'' you can get easily the x then. I think it's proportional to a and b?
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The length of x is essentially the triangle's altitude. It should help to look on http://en.wikipedia.org/wiki/Altitude_(triangle) …
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x=a*sin(arccos(a/c)) Calculate the angle between a and c using cos, then use that angle to calculate x with sin
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This solution is more computationally expensive, but should work with any triangle
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Oh boy! a²+x² + b²+x² = c² a²+b²-c² = -2x² x² = -(a²+b²-c²)/2 x = sqrt(-(a²+b²-c²)/2) But I always flub something. :)
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why is a²+x² + b²+x² = c² true? it doesn't look true
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Heron's formula for the area: https://www.mathopenref.com/heronsformula.html … Then x = (Area*2/c)
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