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Go has GC and Rust doesn't. If you were to design an explicitly C-like language with memory safety and without GC, it would look a lot more like Rust than Go. The idea that Rust was designed by a bunch of C++ fans is absurd. Most of us were ML fans more than anything. t.co/SWJhLJptY3

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Patrick Walton

@pcwalton

Jul 25, 2019

The issue is that generics are basically a requirement for memory safety without GC as Rust does it. Otherwise you can't create safe abstractions, which would mean that every time you want a linked list you have to write unsafe code. That would undermine memory safety.

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I don't follow. Do you claim this is the case if you did it the C way, i.e. without an abstraction or with macros?

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How do you write a function receiving a slice like &[Type] and returning a reference to the initial value as &Type if you don't have generics? It needs to be generic based on the lifetime of the reference even if Type is a specific type rather than a generic type parameter.

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If you don't have a way to do this, there's not much you can do without entirely copying everything over and over to do anything. If the language doesn't have nullable references by default, which is a huge design mistake, my example would also likely return Option<&T> instead.

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Generics and sum types are expected these days for productivity but with the focus on safety they become essential for usability for various reasons. It's very desirable for generics to specify the requirements for the types to specify the API properly and provide proper errors.

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That leads to wanting a feature for specifying interfaces, i.e. type classes. So now you have generics, type classes and sum types as baseline features. Now, how do you implement closures in an efficient way, without forcing allocation or using them solely via generic functions?

9:19 PM · Jul 25, 2019Twitter Web App

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Each is essentially a unique type based on their captures, with a method for calling them. Having closures implement specific interfaces (type classes) makes sense and is what Rust does but you lack a way to work with them in an abstract way rather than unique types via generics.

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So, for example, consider a use case like a work queue where work is supplied as a closure. You need to define a queue data structure with closures. A generic Queue<T> isn't enough because you don't have a specific type. Sum types don't work either, they aren't extensible.

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