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I guess I don't understand the context. It seems to be about C, and I don't see how you can resolve that problem for C without coming up with a model to enforce a form of memory safety. What is the scope of UB that should be avoided? You mean, for a language like Rust or Swift?
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The question of whether memory unsafety implies UB is sort of at the heart of the disconnect between the C spec and C practitioners. As a practitioner (and compiler guy) I view memory unsafety as a separate thing - after all a “bad” store still stores to a well defined place.
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There is nothing well defined about what an out-of-bounds access or use-after-free will access. The compiler, linker and even runtime environment are assuming that is never going to happen and there's nothing defined about what the consequences are going to be from the C code.
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Memory safety is certainly UB and certainly heavily impacted by optimizations. They would need to trap on memory corruption / type confusion bugs in order to get rid of undefined behavior while also still being able to heavily optimize without changing runtime behavior.
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Tons of programs have latent memory corruption bugs and are depending on the specific way that the compiler, malloc implementation, etc. chose to lay things out in memory, what happens to be zeroed based on what they chose to do, etc. It's certainly UB with similar impacts.
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I'm using the term per the standard that came up with this meaning of it. I'd never use that term on my own when designing and defining a language not tied to C or C compilers. It's C standard jargon. Compiler choices certainly matter for memory safety.
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Replying to @DanielMicay @filpizlo and 4 others
Here's something that's undefined: accessing uninitialized data. int a; if (cond1) { a = 5; } else { if (cond2) { a = 10; } } use(a); do_other_stuff(); use(a); Lets say that cond1 & cond2. Should both calls to use(a) be guaranteed to read the same value from uninitialized data?
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