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  1. proslijedio/la je Tweet
    23. ruj 2019.
    Odgovor korisniku/ci

    I wonder if the “freedom dividend” will come with an implicit agreement to buy cricket dust patties instead of burgers? Gov’t-approved menu for the plebes - should work out great! 🙄

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  2. proslijedio/la je Tweet
    23. ruj 2015.
    Odgovor korisniku/ci

    Got scratch paper handy? Write this down: Mix an egg in & dust those patties with corn starch.

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  3. proslijedio/la je Tweet

    I about to eat 2 pizzas and 2 patties because the only things I've consumed in the last 24 hours are coffee, water and dust.

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  4. proslijedio/la je Tweet
    25. velj 2018.
    Odgovor korisniku/ci

    whatever floats ur boat, enjoy ur dust patties

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  5. proslijedio/la je Tweet
    20. ožu 2018.
    Odgovor korisniku/ci

    Archive dust + moisture rolls up into lovely patties...

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  6. proslijedio/la je Tweet
    11. ožu 2019.
    Odgovor korisnicima

    HYDROX RULES! 🤨 Oreo's are grease filled dust patties.

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  7. proslijedio/la je Tweet

    Whoever you are, wherever you are, access to water is a human right.

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  8. proslijedio/la je Tweet
    16. sij
    Odgovor korisniku/ci

    Right, and all I’m saying is the condition is also true when [G/A]<1

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  9. proslijedio/la je Tweet
    16. sij

    Sorry. I read it but could not do any better at the time. The equation should read: 6^5 + 4^5 = [ (6/4)^5 + 1 ] × 4^5 8800 = 8800 G^x + A^x = [ (G/A)^x + 1 ] × A^x G^x - A^x = [ (G/A)^x - 1 ] × A^x When G/A is top heavy and x is any positive integer solution.

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  10. 16. sij

    Sorry. I read it but could not do any better at the time. The equation should read: 6^5 + 4^5 = [ (6/4)^5 + 1 ] × 4^5 8800 = 8800 G^x + A^x = [ (G/A)^x + 1 ] × A^x G^x - A^x = [ (G/A)^x - 1 ] × A^x When G/A is top heavy and x is any positive integer solution.

    Poništi
  11. proslijedio/la je Tweet
    15. sij
    Odgovor korisniku/ci

    My teacher worked this out and I calculated the other one.

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  12. proslijedio/la je Tweet
    15. sij
    Odgovor korisniku/ci

    4^5 + 6^5 = [ (6/4)^5 + 1 ] × 4^5 G^x + A^x = [ (G/A)^x + 1 ] × A^x G^x - A^x = [ (G/A)^x - 1 ] × A^x When G/A is top heavy and x is any positive integer solution.

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  13. proslijedio/la je Tweet
    13. sij

    J.J. Thomson won the Nobel Prize for the discovery of the electron in 1906. He was a very gifted teacher. Six of his research assistants won Nobel Prizes in Physics and two in Chemistry. Thomson's son won the Nobel Prize in Physics for showing that electrons are waves.

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  14. proslijedio/la je Tweet
    14. sij
    Odgovor korisniku/ci

    If overlapping circles are sort of truth algorithm. Then could an infinite amount of randomly overlapping areas point to the supertruth? The area with the most overlapping areas.

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  15. proslijedio/la je Tweet
    14. sij
    Odgovor korisniku/ci

    May be that’s why it’s to hard to prove that absolute zero exist and that we can only approach it from the positive or negative sides.

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  16. 15. sij

    Positive infinity and negative infinity, like 2 rulers meet at zero.

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  17. 12. sij

    Dust patties may be: • made with herbs and spices • sweetened with a little honey • dipped in batter, or • plain simply fry both sides at a high temperature in a frying pan with oil. Make a dust patty with dust and water. Shape into biscuits.

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  18. 8. sij
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  19. proslijedio/la je Tweet
    5. sij
    Odgovor korisniku/ci

    All I know is A^x + A^y = A^z ×(A^x-z + 1/ A^z-y) when x>z>y. What is a Common factor?

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  20. 5. sij

    A 5-egg snack with bacon.

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