There is great concern about the potential spread of the new #SARSCoV2 variant (B.1.1.7) outside the UK. How many cases do we have to expect in Switzerland and will they spread further? Let's do some back-of-the-envelope calculations. 1/nhttps://www.ecdc.europa.eu/en/publications-data/threat-assessment-brief-rapid-increase-sars-cov-2-variant-united-kingdom …
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Around 10,000 British visitors have arrived in Switzerland since December 14. Many of them are visiting Switzerland for their ski holidays. 2/nhttps://www.tagesanzeiger.ch/auf-der-suche-nach-10000-briten-602816416848 …
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The Real-time Assessment of Community Transmission (REACT) programme estimated
#SARSCoV2 RT-PCR swab-positivity (prevalence) in the UK during early December at around 1%. That would correspond to around 100 positive cases among the British visitors. 3/nhttps://www.imperial.ac.uk/medicine/research-and-impact/groups/react-study/real-time-assessment-of-community-transmission-findings/ …1 odpowiedź 7 podanych dalej 57 polubionychPokaż ten wątek -
Assuming that around half of those cases are infectious and another half carry the new variant, there could be around 25 cases with the new variant in Switzerland. What is the probability that they establish a sustained transmission chain in Switzerland? 4/n
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Using branching process models, we can calculate this probability as P = 1 - 1/Re^n where Re is the effective reproduction number and n is the number of initial cases. 5/npic.twitter.com/3JTSlMWGPM
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The effective reproduction number in Switzerland is arguably slightly above 1 at the moment. For Re = 1.05, we obtain a probability of 70% that the new variant will spread in Switzerland. For Re = 1.1, the probability would be 91%. 6/n https://sciencetaskforce.ch/epidemiologische-lagebeurteilung-21-dezember-2020/ …
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W odpowiedzi do @C_Althaus
Isn't Re of the new variant relevant here? Not Re of all the other variants circulating in CH? If (and we don't know for sure) the variant is spreading substantially faster, you'd need to use a higher Re value, right?
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Absolutely, see tweet 11 in this thread. For Re = 1.5 and k = 0.5, we get a probability of ~ 100% that the new variant will start to spread.
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W odpowiedzi do @C_Althaus @richardneher
But I’m still hopeful.
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